Integrand size = 24, antiderivative size = 136 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=\frac {35}{8} d^2 x \sqrt {d^2-e^2 x^2}+\frac {35 d \left (d^2-e^2 x^2\right )^{3/2}}{12 e}+\frac {7 (d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{4 e}+\frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+\frac {35 d^4 \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{8 e} \]
[Out]
Time = 0.04 (sec) , antiderivative size = 136, normalized size of antiderivative = 1.00, number of steps used = 7, number of rules used = 7, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.292, Rules used = {677, 669, 685, 655, 201, 223, 209} \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=\frac {35 d^4 \arctan \left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{8 e}+\frac {35}{8} d^2 x \sqrt {d^2-e^2 x^2}+\frac {35 d \left (d^2-e^2 x^2\right )^{3/2}}{12 e}+\frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+\frac {7 (d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{4 e} \]
[In]
[Out]
Rule 201
Rule 209
Rule 223
Rule 655
Rule 669
Rule 677
Rule 685
Rubi steps \begin{align*} \text {integral}& = \frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+7 \int \frac {\left (d^2-e^2 x^2\right )^{5/2}}{(d+e x)^2} \, dx \\ & = \frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+7 \int (d-e x)^2 \sqrt {d^2-e^2 x^2} \, dx \\ & = \frac {7 (d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{4 e}+\frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+\frac {1}{4} (35 d) \int (d-e x) \sqrt {d^2-e^2 x^2} \, dx \\ & = \frac {35 d \left (d^2-e^2 x^2\right )^{3/2}}{12 e}+\frac {7 (d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{4 e}+\frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+\frac {1}{4} \left (35 d^2\right ) \int \sqrt {d^2-e^2 x^2} \, dx \\ & = \frac {35}{8} d^2 x \sqrt {d^2-e^2 x^2}+\frac {35 d \left (d^2-e^2 x^2\right )^{3/2}}{12 e}+\frac {7 (d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{4 e}+\frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+\frac {1}{8} \left (35 d^4\right ) \int \frac {1}{\sqrt {d^2-e^2 x^2}} \, dx \\ & = \frac {35}{8} d^2 x \sqrt {d^2-e^2 x^2}+\frac {35 d \left (d^2-e^2 x^2\right )^{3/2}}{12 e}+\frac {7 (d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{4 e}+\frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+\frac {1}{8} \left (35 d^4\right ) \text {Subst}\left (\int \frac {1}{1+e^2 x^2} \, dx,x,\frac {x}{\sqrt {d^2-e^2 x^2}}\right ) \\ & = \frac {35}{8} d^2 x \sqrt {d^2-e^2 x^2}+\frac {35 d \left (d^2-e^2 x^2\right )^{3/2}}{12 e}+\frac {7 (d-e x) \left (d^2-e^2 x^2\right )^{3/2}}{4 e}+\frac {2 \left (d^2-e^2 x^2\right )^{7/2}}{e (d+e x)^3}+\frac {35 d^4 \tan ^{-1}\left (\frac {e x}{\sqrt {d^2-e^2 x^2}}\right )}{8 e} \\ \end{align*}
Time = 0.52 (sec) , antiderivative size = 92, normalized size of antiderivative = 0.68 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=\frac {\sqrt {d^2-e^2 x^2} \left (160 d^3-81 d^2 e x+32 d e^2 x^2-6 e^3 x^3\right )-210 d^4 \arctan \left (\frac {e x}{\sqrt {d^2}-\sqrt {d^2-e^2 x^2}}\right )}{24 e} \]
[In]
[Out]
Time = 2.73 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.61
method | result | size |
risch | \(\frac {\left (-6 e^{3} x^{3}+32 d \,e^{2} x^{2}-81 d^{2} e x +160 d^{3}\right ) \sqrt {-x^{2} e^{2}+d^{2}}}{24 e}+\frac {35 d^{4} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-x^{2} e^{2}+d^{2}}}\right )}{8 \sqrt {e^{2}}}\) | \(83\) |
default | \(\frac {\frac {\left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {9}{2}}}{d e \left (x +\frac {d}{e}\right )^{4}}+\frac {5 e \left (\frac {\left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {9}{2}}}{3 d e \left (x +\frac {d}{e}\right )^{3}}+\frac {2 e \left (\frac {\left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {9}{2}}}{5 d e \left (x +\frac {d}{e}\right )^{2}}+\frac {7 e \left (\frac {\left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {7}{2}}}{7}+d e \left (-\frac {\left (-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e \right ) \left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {5}{2}}}{12 e^{2}}+\frac {5 d^{2} \left (-\frac {\left (-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e \right ) \left (-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )\right )^{\frac {3}{2}}}{8 e^{2}}+\frac {3 d^{2} \left (-\frac {\left (-2 e^{2} \left (x +\frac {d}{e}\right )+2 d e \right ) \sqrt {-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )}}{4 e^{2}}+\frac {d^{2} \arctan \left (\frac {\sqrt {e^{2}}\, x}{\sqrt {-e^{2} \left (x +\frac {d}{e}\right )^{2}+2 d e \left (x +\frac {d}{e}\right )}}\right )}{2 \sqrt {e^{2}}}\right )}{4}\right )}{6}\right )\right )}{5 d}\right )}{d}\right )}{d}}{e^{4}}\) | \(403\) |
[In]
[Out]
none
Time = 0.41 (sec) , antiderivative size = 83, normalized size of antiderivative = 0.61 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=-\frac {210 \, d^{4} \arctan \left (-\frac {d - \sqrt {-e^{2} x^{2} + d^{2}}}{e x}\right ) + {\left (6 \, e^{3} x^{3} - 32 \, d e^{2} x^{2} + 81 \, d^{2} e x - 160 \, d^{3}\right )} \sqrt {-e^{2} x^{2} + d^{2}}}{24 \, e} \]
[In]
[Out]
\[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=\int \frac {\left (- \left (- d + e x\right ) \left (d + e x\right )\right )^{\frac {7}{2}}}{\left (d + e x\right )^{4}}\, dx \]
[In]
[Out]
none
Time = 0.28 (sec) , antiderivative size = 156, normalized size of antiderivative = 1.15 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=\frac {35 \, d^{4} \arcsin \left (\frac {e x}{d}\right )}{8 \, e} + \frac {{\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {7}{2}}}{4 \, {\left (e^{4} x^{3} + 3 \, d e^{3} x^{2} + 3 \, d^{2} e^{2} x + d^{3} e\right )}} + \frac {7 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {5}{2}} d}{12 \, {\left (e^{3} x^{2} + 2 \, d e^{2} x + d^{2} e\right )}} + \frac {35 \, {\left (-e^{2} x^{2} + d^{2}\right )}^{\frac {3}{2}} d^{2}}{24 \, {\left (e^{2} x + d e\right )}} + \frac {35 \, \sqrt {-e^{2} x^{2} + d^{2}} d^{3}}{8 \, e} \]
[In]
[Out]
none
Time = 0.29 (sec) , antiderivative size = 69, normalized size of antiderivative = 0.51 \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=\frac {35 \, d^{4} \arcsin \left (\frac {e x}{d}\right ) \mathrm {sgn}\left (d\right ) \mathrm {sgn}\left (e\right )}{8 \, {\left | e \right |}} + \frac {1}{24} \, \sqrt {-e^{2} x^{2} + d^{2}} {\left (\frac {160 \, d^{3}}{e} - {\left (81 \, d^{2} + 2 \, {\left (3 \, e^{2} x - 16 \, d e\right )} x\right )} x\right )} \]
[In]
[Out]
Timed out. \[ \int \frac {\left (d^2-e^2 x^2\right )^{7/2}}{(d+e x)^4} \, dx=\int \frac {{\left (d^2-e^2\,x^2\right )}^{7/2}}{{\left (d+e\,x\right )}^4} \,d x \]
[In]
[Out]